A 10 Ω resistor carries 2 A. What is the power dissipated, and what is the voltage across it?

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Multiple Choice

A 10 Ω resistor carries 2 A. What is the power dissipated, and what is the voltage across it?

Explanation:
Power in a resistor comes from the current through it and the resistance, via P = I^2R and V = IR. With a current of 2 A and a resistance of 10 Ω, the voltage across the resistor is V = I R = 2 × 10 = 20 V. The power dissipated is P = I^2 R = (2)^2 × 10 = 4 × 10 = 40 W. This also matches P = V I = 20 × 2 = 40 W, confirming consistency. So the resistor dissipates 40 W and has 20 V across it.

Power in a resistor comes from the current through it and the resistance, via P = I^2R and V = IR. With a current of 2 A and a resistance of 10 Ω, the voltage across the resistor is V = I R = 2 × 10 = 20 V. The power dissipated is P = I^2 R = (2)^2 × 10 = 4 × 10 = 40 W. This also matches P = V I = 20 × 2 = 40 W, confirming consistency. So the resistor dissipates 40 W and has 20 V across it.

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